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Date: 20-11-2020
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Date: 18-1-2021
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Date: 14-7-2020
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Pythagoras's theorem states that the diagonal of a square with sides of integral length
cannot be rational. Assume
is rational and equal to
where
and
are integers with no common factors. Then
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so
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and , so
is even. But if
is even, then
is even. Since
is defined to be expressed in lowest terms,
must be odd; otherwise
and
would have the common factor 2. Since
is even, we can let
, then
. Therefore,
, and
, so
must be even. But
cannot be both even and odd, so there are no
and
such that
is rational, and
must be irrational.
In particular, Pythagoras's constant is irrational. Conway and Guy (1996) give a proof of this fact using paper folding, as well as similar proofs for
(the golden ratio) and
using a pentagon and hexagon. A collection of 17 computer proofs of the irrationality of
is given by Wiedijk (2006).
REFERENCES:
Conway, J. H. and Guy, R. K. The Book of Numbers. New York: Springer-Verlag, pp. 183-186, 1996.
Gardner, M. The Sixth Book of Mathematical Games from Scientific American. Chicago, IL: University of Chicago Press, p. 70, 1984.
Pappas, T. "Irrational Numbers & the Pythagoras Theorem." The Joy of Mathematics. San Carlos, CA: Wide World Publ./Tetra, pp. 98-99, 1989.
Wiedijk, F. (Ed.). The Seventeen Provers of the World. Berlin: Springer-Verlag, 2006.
Hardy, G. H. and Wright, E. M. An Introduction to the Theory of Numbers, 5th ed. Oxford, England: Clarendon Press, 1979.
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